jk flipflop

will the characteristic table for j kprime(complement of k) be the same as for jk flipflop.

Yes, except that you have to invert the K logic.

eg. it will toggle when J = 1 & K = 0, etc.

The reason for the inversion is that, if you tie J and K together, it acts as a D flipflop.

For JK flipflop: Q = J&~Q or ~k&Q

For JK` flipflop: Q = J&~Q or KQ

BrownOut said:

For JK flipflop: Q = J&~Q or ~k&Q

For JK` flipflop: Q = J&~Q or KQ

Click to expand...

Don't understand your logic.

For a JK' flipflop after the next clock pulse:
For J=K'=1 ---- Q=1
For J=K'=0 ---- Q=0
For J=1 K'=0 -- Q=Q'
For J=0 K'=1 -- Q=Q

They are the same:

For J=K'=1 ---- Q=1 <=> Q = K&Q

For J=K'=0 ---- Q=0 <=> Q = K&Q ( in this case, Q=0)


For J=1 K'=0 -- Q=Q' <=> Q = J & ~Q or K&Q (in this case, the second term, K&Q, not satisfied)

For J=0 K'=1 -- Q=Q <=> Q = K &Q,

What I posted is just a short-hand version of the same thing, which makes it easier to remember... for me anyway. I know it's a little confusing. Just keep staring at it, or else just forget I posted it