INT to Char

[AtomSoft]

Hey guys i have a number lets say 255 (0xFF)

I want to add 8 to it to make 0x0107(263) then divide it by lets say 16 to get approx 16 as the result (0x0010) now the problem is placing that new value into a char?

How can i place 0x0010 in to a char to make 0x10 ?

 

[kchriste]

int result = 16;
unsigned char destination;

destination = (unsigned char)result;

 

[AtomSoft]

Awesome!!! i had code somewhat like that but it was a pointer version heh

The * just had to come off .... Thanks a bunch

 

[kchriste]

Without the * it is called a CAST. It is not always needed in C, but it is one way to assure that the compiler does exactly what you want.

 

[Mr RB]

Since this is for a corrected integer rounded division you could do this;

unsigned char result;
if(blah > (255-8)) result  = 16;
else result = ((blah+8) / 16);

Which gives exactly the same output but only requires a char variable for result, saving one ram and a heap of ROm as it doesn't need any 16bit math.

 

[AtomSoft]

This is my current routine: converts 8 bit RED to 4 bit RED:

        temp = (((UINT)buff[5] + 8) /16);
        if(temp == 16) temp-=1;
        buff[5] = (BYTE)temp;

 

[Sceadwian]

8 bit to 4 bit? Just divide it by 16.