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input to transformer

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johnsonjp34

New Member
Greetings All,

I'm trying to build a voltage multiplier that is fed by a audio output transformer (273-1380). My source is a 9 V battery. My question is how do I convert the DC to AC so that it will work in the transformer? Can I make a square wave generator out of something like a 555 to feed the transformer or something like a lm358 or some other op amp? I don't quite understand what an op amp does in inverting mode. Is the output on an inverting op amp a form of AC?

Thanks,

JJ
 

Reloadron

Well-Known Member
Most Helpful Member
Yes, there are several popular circuits out there using a 555 to drive that transformer. You drive the 8 Ohm side (secondary) and get your output off the primary side. About all you will manage to do is ionize a NE2 lamp but it does work. What exactly are you trying to do?

Ron
 

johnsonjp34

New Member
I've got some gieger tubes so I'm trying to build a gieger counter. Ionizing is exactly what I want. I'll look around for some 555 plans. Anyone have any that they recommend?
 

Reloadron

Well-Known Member
Most Helpful Member
This link shows a simple neon lamp power source. However, as I mentioned it really does not provide any current to speak of. About all it does is get a NE2 bulb to glow. To get it right this would go much, much better if you could define the voltage and current you need?

Ron
 

johnsonjp34

New Member
These are the stats on the tube:

Working Voltage 380-460V

Working Current 0.015-0.02 mA

I have a bunch of 0.033 uf 200v capacitors and 200v fast recovery diodes sitting around for the voltage multiplier.

Thanks,

JJ
 

audioguru

Well-Known Member
Most Helpful Member
420V at 18mA is 7.56W.
A little 555 can produce only about 1.2W.
The transformer produces a voltage and current much too low.
A voltage multiplier will reduce the output current even more.
 

audioguru

Well-Known Member
Most Helpful Member
If the gieger tube uses only 20uA then a transformer with a higher stepup ratio and better insulation will produce the higher voltage from a 555.
Maybe the transformer from an old camera's flash circuit.
 
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