I want to use the INA122 as a current shunt amplifier. I have attached the schematic here. I want to know before I connect this to power whether it is correct or not. The two diodes are to drop the voltage to the + and - pins by about 1.2V
BTW when I simulate the circuit it does not work !!!!!!!!!!!!!!!!
I want to use the INA122 as a current shunt amplifier. I have attached the schematic here. I want to know before I connect this to power whether it is correct or not. The two diodes are to drop the voltage to the + and - pins by about 1.2V
BTW when I simulate the circuit it does not work !!!!!!!!!!!!!!!!
According to the IC schematic given in the datasheet this should work fine without a Rg resistor. But anyway I put a 200k (which gives a gain of 6) and simulated in multisim. Still it is not the right O/P.
BTW when I do this it works
The data sheet says "Signal Input Terminals, Voltage(2) ....................... (V–)–0.3V to (V+)+0.3V" Does this mean that the inverting and non inverting inputs can go upto 35.9V in my case ?
TI makes a dedicated current shunt monitor amps. I am using an INA195 for a project right now. It has a common mode range from -16 to +80V, regardless of the operating voltage.
I'm running it at +5V power, but measuring the current through a resistor at +14Volts.