an ideal voltage source has an internal resistance of zero. this means that it can deliver any current while its voltage is not affected, right? If so then what will happen if I put a zero resistor to its terminals or short its terminals?
If I put a voltmeter across a such supplier then what what do I''ll read when I short the supplier?
The circuit theory says that you can't short circuit an ideal voltage current, because as you said its internal resistance is "0". And you can not either left in open circuit an ideal current source because its internal resistance is infinite.
The circuit theory says that you can't short circuit an ideal voltage current, because as you said its internal resistance is "0". And you can not either left in open circuit an ideal current source because its internal resistance is infinite.
Can somebody explain it mathmatecaly to me? When you short a voltage source then how does it feeds another load which is parallel to that shorted pin??!
Can somebody explain it mathmatecaly to me? If you make the calculus you will have an infinite current, and that mathematically is right, but the circuit theory says that you can't short circuit that source.
When you short a voltage source then how does it feeds another load which is parallel to that shorted pin??! It couldn't, because no current will flow through a load that is bigger than "0" when there's a short circuit.
Can somebody explain it mathmatecaly to me? When you short a voltage source then how does it feeds another load which is parallel to that shorted pin??!