Eric: Great, thanks. So from the PDF, if I wanted to allow 200ma through C and E, the graph says the hFE will be about 180, so the Ib needed is 200/180 = 1.1 mA. Then 5v - 0.7v / 1.1 = 3.9k resistor is needed.
It seems to say that Vce is mostly just used for amplifying circuits and for switching purposes Vce should be 0 (I'm guessing you don't need to do anything to make it 0 Vce?) which allows the maximum current to be obtained when you apply the current to Ib.