Since my electronic class had no Lab I am trying to learn this on my own 50 years later. My digital meter shows my home made choke is 6.6mh. These mosfets explode at 35 amps I would like to have current no higher than 30 amps. Ohms law shows a .4 ohm resistor will limit current to 30 amps. XL=2 pi FL online calculator shows my choke is 2,654 ohms. My digital metal shows this circuit runs at 64KHz with no load, a 3/8" diameter steel rod drops the frequency to 60 KHz. With the 6.6uh choke in the circuit meter reads 1.5 amps no load and 10 amps with the 3/8" steal rod as a load. It appears to me 2,654 ohms of inductance is different than .4 ohms of resistance??? It seems logical to me if I make another choke that is 885 ohms circuit amps will be 30. It is not logical to me that 885 ohms of inductance is the same as .4 ohms of resistance? I should probably use actual battery voltage to do math instead of 12V because 13.2v = 33 amps in this circuit. Choke is 15 turns of wire, 15/3= 5 turns is it logical to assume 5 turns will drop 6.6uh to 2.2uh?