High side discharge current measurement from 1.2V battery needs many components?

Hello,
The below circuit gives a positive output voltage which corresponds to the current in the sense resistor.
(i.e. output to the micro is referenced to ground even though 'vout' of LT1787 is referenced to -3V, because the opamp circuit has 'level-shifted' it)

-Is their a lower-component-count method of level shifting a voltage that's referenced to -3V, to being referenced at ground?


LT1787 CURRENT MONITOR DATASHEET:
https://cds.linear.com/docs/en/datasheet/1787fc.pdf

LTspice simulation and schematic attached

There are some ready-made chips to measure current such as INA282.

thanks
https://www.ti.com/lit/ds/symlink/ina282.pdf
..from the datasheet the INA282 appears superior to the LT1787 in many respects, and I thought Linear.com always were the last word in quality.

To do the job I want here with the INA282, it looks like all I would need would be a boost converter to provide the INA282's 2.7V minimum input voltage ("V+").

In other words, the INA282 is far more suitable than the LT1787?

I find it bizarre that INA282 seems to be able to have the sense voltage well outside of its supply rail.

Though on page 8 of the LT1787 datasheet they give great diagrams indicating the step response of LT1787. The INA282 datasheet does not appear to give this information...this current monitor will be used in a current regulator, so I need high bandwidth preferably.

You can do it with a op configured as a differential amplifier which is basically what that ic does.
An LMC series op amp chip can operate very close to the supply rail so you might not need a seperate power supply.