Your circuit is of a non-inverting amplifier. When the amp is working in linear mode (ie. when the output is not being switched hard to the +ve or -ve rails) the output will force the -input to closely follow changes at the +input. What happens at the output depends on the resistor/capacitor feedback network R9/C7 and R10/C6.
At low frequencies, eg. 50Hz,the reactances of C6 and C7 are very high, so the only effective feedback component is R9. That allows all the output voltage to be fed to the -input and the amp will have unity gain.
As the frequency is increased, the reactance of C6 will decrease. The voltage fed back to the -input will be partially shunted to ground through R10 and C6, and so the output needs to have a greater amplitude to get enough equalising voltage to feed back to the -input. So as the frequency increases the gain will start to increase at the rate of 6dB per octave with the 3dB point at 3.18KHz (where the reactance of C6 equals R10).
As the frequency is further increased, the reactance of C7 comes into play - shunting R8 and effectively increasing the feedback. The output will start to reduce at 6dB /octave with the 3dB point at 33.86KHz. At frequencies above that C7 becomes progressively more effective and the gain will again reduce to unity.
The circuit is therefore a bandpass filter with a bandwidth from 3.18KHz to 33.86KHz.
The 'soft clipping' diodes will stop the output exceeding the input by 0.7V- for either polarity.
The 'hard clipping' diodes serve no purpose unless the input is DC referenced to ground in some way - but the circuit does not indicate this.