So on to the questions:
The datasheet for these displays shows a 4V forward and 5V reverse voltage. So I need a 5V power supply, right? Can I just stack three (or four?) 1.5V batteries together, or do I need a more complicated power supply?
Steady current is given as 30 mA. So is this just a current divider problem? 5V/0.03 = 167 ohms, so I should put 167 ohms in series for each segment?
so I should put 167 ohms in series for each segment?
Is there anything else that should be included on this simple circuit--capacitors, shunt resistors, other things I'm too ignorant to know about?
If you understand what I'm trying to do, is there anything that could improve the "coolness" factor of this, without making it too complicated (don't want people frustrated out in the middle of the woods on a multi-stage)?
I took a look at the ratings of some common brands to get an idea of how long they would last. If I assume that, on average, half the segments will be lit when the lid is opened (I'll have a limit switch on the lid), then at 25mA per segment this thing would draw 21 x 0.025 = 0.525A. For a battery like the standard Energizer 9V, the datasheet shows about 300mAh at 500mA discharge. So I think that means it would last for less than an hour of operation.
If I stacked four alkaline AA's, each battery would supply 1/4 of the current, so they would be delivering about 125mA each.
When batteries are arranged in series, ALL the current required for the circuit will come from every battery. To have a battery supply only a portion of the operating current the batteries must be arranged in parallel but then the voltages don't add up. You can add up volatges or you can spread out the current draw but unfortunately you can't have both.
For one thing, you could have a momentary switch to power the whole thing. A momentary switch is one that returns when you let go. That way, anyone wanting to look at the display holds the switch on while looking at the display, but as soon as they let go it stops taking power at all.
How would you feel about a microcontroller solution? You could have it reset everytime the lid was closed and then have it create a new random pattern everytime the lid is re-opened.
I did think about that (but I would have no idea about how to actually implement it)
The problem is, there would be 128 different solutions for the seven switch positions. If the solution is random, they'll have to just try every possible combination until they hit paydirt--and I suspect they'll just get frustrated and give up. So I was planning on giving them a clue about the required switch positions on the cache web page--which would require the solution to be singular.
That being said, a random solution generator would be a lot more interesting to build
Any ideas on how I could have a set of possible solutions, and clue them in to it?
There is always a Microcontroller (would need a 5Vdc reg, and a 10000uF cap), it could do some cool stuff.
That being said, a random solution generator would be a lot more interesting to build
Any ideas on how I could have a set of possible solutions, and clue them in to it?
No its not a typo.
It is more for momentary power loss, so that the PIC wouldn't reset.
Or even a 1 FARAD 5.5 VOLT "SUPER CAP" for $3.50 (www allelectronics com CAT# CBC-17)
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