If you wish for the FET to come on, on power up, then a simple solution woud be to invert the output of the 555. Can be done with a transistor (bipolar) or logic inverters.
Pin 7 is an open collector output which is 'low' when the output is low. You could add a PNP transistor to that, with a base resistor and pull up, and simply connect that 10Mohm resistor to that. Its not ideal as you're adding 4 extra parts, but it'll work.
If you don't want the switch function at all, and jsut want it to 'come on permenantly' when you appliy power, just disconnect the 10M resistors to the FET's gate, and connect it to the V+ line (pin 8, or 4 of the 555). Pretty much makes the entire circuit pointless though.
I've editted out other idea's because I jsut thought of something simple. Add a capacitor, say 10n, to 100nF across R2. From ground to Pin 2/6. The rationale for this is that, upon power up, the only things connected to the trigger/threshold pins are two resistors, setting the voltage at VCC/2. The 555 probably defaults to 'output low' when neither its internal SR flipflops set/reset inputs are triggered. However, with a small capacitor across R2, on power up, this cap brings the treshold voltage below VCC/2, triggering the 555, and turning it on.
As for its effect on 'normal' operation, I'm fairly sure, as long as the caps value is small (<47nF say) it shouldn't adversly affect the switches operation, and only server to trigger the output on powerup. Good luck!