Hello again,
Well the nice thing here is that it looks like those elements are mostly resistive, so that makes things a little easier.
You could double check though by testing with a varied voltage and see if they obey Ohm's Law.
PWM works better into a purely resistive load. We could crunch some numbers to look into this more.
A requirement is that the switch element has as little series resistance as possible. MOSFET's have low resistance if you buy the right ones.
But from your first schematic it looks like one element is 4 ohms and the others are 6, and since they are in parallel we have the same voltage going to all of them, so we calculate the power with say 6 volts applied:
Pr6=6^2/6=36/6=6 watts
Pr4=6^2/4=36/4=9 watts
Now the question is, if both elements are the same diameter, then the heat concentration for the 4 ohm device is 1.5 times greater than the 6 ohm devices, so is this what you really want? The heat concentration would be measured in watts per square inch for example. That means there will be more local heating for one element than the others, or in other words, a "hot spot".
If that is what you want then that's great, but if not then you have to look at it a little closer.
The heating power of 100 percent duty cycle PWM with 6v applied to a 6 ohm load is 6 watts.
The heating power of 50 percent duty cycle PWM with same is 3 watts.
The heating power of 25 percent duty cycle PWM with same is 1.5 watts.
The temperature rise is dependent on the specific heat capacity of the material(s) and the power applied. Twice the power heats something up twice as fast, given little heat loss.
Heating is usually a slow process so you probably dont need any extravagant control schemes

Measure the difference between the current temperature and the set point temperature, integrate with a long time constant to create the control signal, and you're probably doing just fine. The control signal to PWM signal ratio is one to one.
Any chance you would want to make a heating AND cooling jacket with Peltier devices?