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have some questions here....

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In an AC analysis:

what effect would it be made for a capacitor connected in series with a resistor to the total current opposition of the circuit? can the voltage of the two elements be solved using voltage divider? how about in parallel?

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Capacitors and inductors have a reactive impedance proportional to the frequency with voltage and current through them 90 degrees out of phase, thus you need you use complex numbers to calculate the resultant impedance when they are connected together and to resistors. But you can use standard component series and parallel equations for the solution and long as you use phasor (complex number) calculations.
 
Hi,

For just one resistor connected in series with one capacitor connected also in series with an AC voltage source the solutions are:

vC=Vs/sqrt(w^2*C^2*R^2+1)
THC=-atan(w*R*C)

vR=Vs*w*C*R/sqrt(w^2*C^2*R^2+1)
THR=atan(1/(w*R*C))

I=Vs*w*C/sqrt(w^2*C^2*R^2+1)
THI=atan(1/(w*R*C))

vC is the AC voltage across the capacitor, vR is the AC voltage across the resistor, I is the AC current, THC is the phase shift of the voltage across the capacitor, THR is the phase shift of the voltage across the resistor, THI is the phase shift of the current, w is the angular frequency w=2*pi*f, f is the frequency in Hertz.
All phase shifts relative to the AC source voltage (Vs) phase.
 
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