transgalactic
Banned
here is a solution with different resolt then mine
i cant understand where is my mistake
https://i50.tinypic.com/1rul4p.jpg
we need to find V1 and V2 and i_phi
i signed the potentials on the intersection as v1 and v2 .
kcl for v1 intersection:
[latex]
-\left ( \frac{8i_{\phi}-v_1}{2} \right )+\frac{v_1}{10}-\left ( \frac{v_2-v_1}{5} \right )=0
[/latex]
[latex]
-\left ( \frac{8\left ( \frac{v_2-v_1}{5} \right )-v_1}{2} \right )+\frac{v_1}{10}-\left ( \frac{v_2-v_1}{5} \right )=0\\
[/latex]
kcl for v2 intersection:
[latex]
-\left ( \frac{20-v_2}{2} \right )+\frac{v_2}{20}-\left ( \frac{v_2-v_1}{5} \right )=0\\
[/latex]
i got v1=20
v2=24
i_phi=4/5
my currents are pointed exactly as in the solution except the current which comes from the voltage source
in my solution it goes in the intersection.
i say that a current which goes inside signed as + and
its signed as - otherwise.
and as current goes the potential decreases
so i subtracted to higher potential with the lower potential divided by the ressistor between the
and put a minus if the current goes inside the intersection
i cant understand where is my mistake
https://i50.tinypic.com/1rul4p.jpg
we need to find V1 and V2 and i_phi
i signed the potentials on the intersection as v1 and v2 .
kcl for v1 intersection:
[latex]
-\left ( \frac{8i_{\phi}-v_1}{2} \right )+\frac{v_1}{10}-\left ( \frac{v_2-v_1}{5} \right )=0
[/latex]
[latex]
-\left ( \frac{8\left ( \frac{v_2-v_1}{5} \right )-v_1}{2} \right )+\frac{v_1}{10}-\left ( \frac{v_2-v_1}{5} \right )=0\\
[/latex]
kcl for v2 intersection:
[latex]
-\left ( \frac{20-v_2}{2} \right )+\frac{v_2}{20}-\left ( \frac{v_2-v_1}{5} \right )=0\\
[/latex]
i got v1=20
v2=24
i_phi=4/5
my currents are pointed exactly as in the solution except the current which comes from the voltage source
in my solution it goes in the intersection.
i say that a current which goes inside signed as + and
its signed as - otherwise.
and as current goes the potential decreases
so i subtracted to higher potential with the lower potential divided by the ressistor between the
and put a minus if the current goes inside the intersection
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