#### transgalactic

##### Banned

here is a solution with different resolt then mine

i cant understand where is my mistake

https://i50.tinypic.com/1rul4p.jpg

we need to find V1 and V2 and i_phi

i signed the potentials on the intersection as v1 and v2 .

kcl for v1 intersection:

[latex]

-\left ( \frac{8i_{\phi}-v_1}{2} \right )+\frac{v_1}{10}-\left ( \frac{v_2-v_1}{5} \right )=0

[/latex]

[latex]

-\left ( \frac{8\left ( \frac{v_2-v_1}{5} \right )-v_1}{2} \right )+\frac{v_1}{10}-\left ( \frac{v_2-v_1}{5} \right )=0\\

[/latex]

kcl for v2 intersection:

[latex]

-\left ( \frac{20-v_2}{2} \right )+\frac{v_2}{20}-\left ( \frac{v_2-v_1}{5} \right )=0\\

[/latex]

i got v1=20

v2=24

i_phi=4/5

my currents are pointed exactly as in the solution except the current which comes from the voltage source

in my solution it goes in the intersection.

i say that a current which goes inside signed as + and

its signed as - otherwise.

and as current goes the potential decreases

so i subtracted to higher potential with the lower potential divided by the ressistor between the

and put a minus if the current goes inside the intersection

i cant understand where is my mistake

https://i50.tinypic.com/1rul4p.jpg

we need to find V1 and V2 and i_phi

i signed the potentials on the intersection as v1 and v2 .

kcl for v1 intersection:

[latex]

-\left ( \frac{8i_{\phi}-v_1}{2} \right )+\frac{v_1}{10}-\left ( \frac{v_2-v_1}{5} \right )=0

[/latex]

[latex]

-\left ( \frac{8\left ( \frac{v_2-v_1}{5} \right )-v_1}{2} \right )+\frac{v_1}{10}-\left ( \frac{v_2-v_1}{5} \right )=0\\

[/latex]

kcl for v2 intersection:

[latex]

-\left ( \frac{20-v_2}{2} \right )+\frac{v_2}{20}-\left ( \frac{v_2-v_1}{5} \right )=0\\

[/latex]

i got v1=20

v2=24

i_phi=4/5

my currents are pointed exactly as in the solution except the current which comes from the voltage source

in my solution it goes in the intersection.

i say that a current which goes inside signed as + and

its signed as - otherwise.

and as current goes the potential decreases

so i subtracted to higher potential with the lower potential divided by the ressistor between the

and put a minus if the current goes inside the intersection

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