Does Current Monitor gain (x10) appear in transfer function of BuckBoost feedback loop ?

Hello,
In the attached schematic (and LTspice simulation) of a buckboost converter, the LED current sense resistor voltage is multiplied by 10 by the Current monitor (LTC6101).
Should this factor of 10 appear in the small signal Error amplifier transfer function for the purposes of plotting out the Bode plots and assessing the gain and phase margin?

The answer is yes, since that amplified voltage is part of the feedback loop.

Why do you have both a 5V and 9V supply? Couldn't you use 9V for both?

thanks, the 5v is needed for the 'el cheapo' opamps that ill actually be using.