Hi all, I am a second year student (old timer) and my disciplin is in Computer and electronic enginnering.I am really finding it hard to understand diffeentiation. I can understand the concept but putting this beyond first principles is beyond me. I know i really want to learn this as i know it will come up time after time. If any of you out there can help, i would really appreciate it. Thanks
Hi all, I am a second year student (old timer) and my disciplin is in Computer and electronic enginnering.I am really finding it hard to understand diffeentiation. I can understand the concept but putting this beyond first principles is beyond me. I know i really want to learn this as i know it will come up time after time. If any of you out there can help, i would really appreciate it. Thanks
When you first start to get into this it sometimes helps to look at numerical
differentiation first before getting into full blown differentiation.
The numerical derivative of a function is:
f'(x)=(f(x+h)-f(x))/h
where
f(x) is the function
h is a small increment, like 0.001 .
As h gets smaller and smaller, the above equation approaches the
exact derivative at a point x.
As you get going with this, it also helps to look up some common
derivatives like the derivative of x, of x^2, of x^3, etc., and the
formulas that are used to find the derivatives.
For example, the derivative of x^2 is 2*x, and the derivative of
x^3 is 3*x^2, and the general formula for the derivative of
x^N is N*x^(N-1). This isnt too hard to do, but sometimes
the technique is a little more involved so you end up looking
up various methods and sometimes even consult a table
of derivatives. Some math handbooks have extensive tables.
If you would like more help with this, try asking some more
specific questions, like what is the derivative of sin(x) or
something like that. You'll find that eventually you can
find the derivative for almost any function.
When I first tried to learn calculus I found it very confusing. I just didn't understand what I was trying to find. When I discovered that I was trying to find the slope of the graph then dy/dx suddenly made sense.
My wife (mid 40's) is currently doing a refresher course at uni as she is a teacher and I'm explaining lots of this stuff to her at the moment. If you have any examples of stuff you don't understand then post them, I'm sure there are lot's of posters willing to help.
Mike.
Edit, I thought I had better add, in my wifes defense, she hasn't taught for 20 years as she was a Mother to our children. To her credit, she is doing a refresher course rather than go ill equipped into a classroom.
d {(2t-1)/((3t))^2 +(5t)}/dt
is this your problem
so i think you know the partial fraction expansion
then then we can write
(2t-1)/((3t))^2 +(5t) =(2t-1)/(9*t^2 +5t)=(2t-1)/t(9t+5)=a/t+b/(9t+5)
where "a" and "b" are real constants
then
(2t-1)/t(9t+5) =(a(9t+5)+bt)/t(9t+5) =[(t(9a+b))+5a]/t(9t+5)
so considering constant term in both side of above equation
we can get
a=-1/5
and considering "t" terms we can get
b=11/5
so we can simplify given function to
d {(2t-1)/((3t))^2 +(5t)}/dt=d {(-1/5t+(11/5(9t+5)) }/dt
d {(-1/5t+(11/5(9t+5)) }/dt= d {(-1/5)t^-1+(11/5)(9t+5)^-1) }/dt
so
it is
d {(2t-1)/((3t))^2 +(5t)}/dt=1/[5(t^2)] - 99/[5(9t+5)^2]
go it
Well, hopefully you got some help from the above posts. If you did then maybe if you posted what you gained (now understand) from the above posts then others may benefit.
Do you now have a better understanding of,
the chain rule,
the product rule,
the quotient rule.
If you can explain your thought process then people that read this in the future may get a better understanding of the whole process. If, on the other hand, your still struggling with a particular part of differentiation then just ask.
Well, common usage is to call dD/dt 'velocity', which is signed.
Speed, on the other hand, is often taken to exclude the sign,
which removes the directional sense, so that common usage
would mean:
Velocity=dD/dt
and
Speed=abs(Velocity)=abs(dD/dt)
where
abs(x)=|x|=absolute value of x
Also for reference, s is often used for distance instead of D as
used above.
Well, common usage is to call dD/dt 'velocity', which is signed.
Speed, on the other hand, is often taken to exclude the sign,
which removes the directional sense, so that common usage
would mean:
Velocity=dD/dt
and
Speed=abs(Velocity)=abs(dD/dt)
where
abs(x)=|x|=absolute value of x
Also for reference, s is often used for distance instead of D as
used above.