converting uart string to int mikroc

Varunme · Mar 20, 2012

How can i convert the uart strings to int in mikroc?

i attempted

atoi(uart_rd);

and

added a '\0' to uart_rd and sent to atoi, that too not working

Ian Rogers · Mar 20, 2012

atoi() should work....... Have you an example of the string you're trying to convert...

There is possible characters, that atoi() can't handle

Varunme · Mar 20, 2012

i send single characters of

1, 2, 3 etc

when i used

char sec ="123";

it worked
by using uart , its not working

Varunme · Mar 20, 2012

Code:

while(1)
     {
        delay_ms(200);
        if (UART1_Data_Ready())
        {

            on = UART1_Read();
            on2 = strcat(on,"\0");
            
            
                         
             
            intme = atoi (yon2);
                     

           
          for(rot=0; rot<=intme; rot++)
          {

                 PORTB=0b00010000; delay_ms(200);
                 PORTB=0b00001000; delay_ms(200);

                 }
                  }
        }

Varunme · Mar 20, 2012

whatever i send, i get the loop only one time

misterT · Mar 20, 2012

How do you declare the "on" variable?
What does "UART1_Read();" return?

I think it should be something like this:

Code:

char on[10];   // char table to store received string
int intme;

// Check if character is ready for reading and read it.
if (UART1_Data_Ready() == 1) { 
    on[0] = UART1_Read();   // read one character from uart
    on[1] = '\0';           // insert terminating zero
}

intme = atoi(on);

The above code should read one character from uart (if available) and convert it with itoa.

Varunme · Mar 20, 2012

Then how can i convert , if i have to send a character like "100" to uart ?,

can be done by increasing the size of on[] array ? by taking the strlen ?

Varunme · Mar 20, 2012

This is my final code, but even with single character, the program not working

Code:

void main(){
unsigned char txt[2];
int y,rot;
char on[10];   // char table to store received string
int intme;
trisb=0x00;
portb=0x00;

    UART1_Init(9600);



// Check if character is ready for reading and read it.
        if (UART1_Data_Ready() == 1) {
        on[0] = UART1_Read();   // read one character from uart
        on[1] = '\0';           // insert terminating zero
}

 
    
          for(rot=0; rot<=atoi(on );  rot++)
          {

                 PORTB=0b00010000; delay_ms(200);
                 PORTB=0b00001000; delay_ms(200);

                 }
                 }

Varunme · Mar 21, 2012

yes, its working finally

misterT · Mar 21, 2012

Varunme said:
Then how can i convert , if i have to send a character like "100" to uart ?

You can use the "UART1_Read_Text()" function to read multiple characters. Here is a library reference with example code:
**broken link removed**

Varunme · Mar 21, 2012

when i tried

on[7] = UART1_Read_Text(output, "m", 255); // read one character from uart
on[8] = '\0'; // insert terminating zero

it says

"illegal expression with void"

Ian Rogers · Mar 21, 2012

on[7] = UART1_Read_Text(output, "m", 255);

No.... this function allows you to pass a buffer..... "output" a delimiter "m" and re-try "255" but returns a void.... so " on[7] " will receive an illegal qualifier.

misterT · Mar 21, 2012

"UART1_Read_Text()" -function does not return anything. It takes three parameters.
- char array to store the received text
- sequence of characters that identifies the end of a received string
- expected string length (or 255 if not known).

So, the piece of code that should work in your example should be:

UART1_Read_Text(on, "m", 255);

If you send something like "93m", the above line of code should be able to read and store the string "93" in the variable "on".

You should probably learn how string arrays work in C language:
**broken link removed**

Do you have trouble understanding the library reference?

Varunme · Mar 21, 2012

yes,

I modified it as

Code:

void main(){
unsigned char txt[2];
unsigned char output[7];
int y,rot;
char on[28];   // char table to store received string
int intme;
trisb=0x00;
portb=0x00;

    	UART1_Init(9600);

	while(1){

	while (!UART1_Data_Ready());        // wait for UART character in buffer
	
	UART1_Read_Text(output, "m", 255);   // read one character from uart

	y=strlen(output);
     
	on[y]=output;
	on[y+1]='\0';        // insert terminating zero
    

          for(rot=0; rot<=atoi(on)-1; ++rot)
          {

                 PORTB=0b00010000; delay_ms(200);
                 PORTB=0b00001000; delay_ms(200);

                }
		}

       }

is it something wrong with it ? , its not working

misterT · Mar 21, 2012

Varunme said:
is it something wrong with it ? , its not working

Yes. You cannot copy a string like this:
on[y]=output;

You don't even need to copy the string. You can use the "output" variable with the atoi().

Code:

void main(){
char output[7];
int i,rot;
trisb=0x00;
portb=0x00;
 
UART1_Init(9600);
 
while(1){
 
	while (!UART1_Data_Ready());        // wait for UART character in buffer

        // Initialize string with all '\0'
        for(i=0; i<7; i++){
            output[i] = '\0';
        } 

	UART1_Read_Text(output, "m", 255);   // read input from uart
 
        for(rot=0; rot<=atoi(output)-1; ++rot)
        {
               PORTB=0b00010000; delay_ms(200);
               PORTB=0b00001000; delay_ms(200);
        }
}
}

Ian Rogers · Mar 21, 2012

Your input is in the output buffer.... there is no need for the "on[y]; " just do " rot = atoi(output); " or " on[y] = output[y] ;"

Ian Rogers · Mar 21, 2012

Right... I'll stop posting... as me and Mr T are giving the same answers

Varunme · Mar 21, 2012

But i am getting the loop once, not an infinite while loop.

Ian Rogers · Mar 21, 2012

Because of the data ready routine..... is the data coming continuously?

Varunme · Mar 21, 2012

yes,

once i send the data with 'm' termination,

after some time the data will come with another 'm' termination.

so data coming continously

How can i correct it for continous ?

converting uart string to int mikroc

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