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Could anybody tell me which of Fig A or Fig B is the proper circuit.
The problem is that in Fig A the Battery supply is connected to Drain and in Fig B it is connected to Source.
He didn't ask if they were pfets, he was confused about which circuit works. But as ROFF said we can't answer the question till he explains what is supposed to be driving the gates.
As you can see from the diagram there is a pull up resistor, so if nothing else is driving then the gate is maintained at low or 0V. The other condition is a 5V supply being constant on the gate pin.
The question is Which of the two diagrams have the Drain and Source Pins rightly positioned?
This appears to be a supply switchover circuit. The correct circuit has to be Fig. A. Assuming the 5V is capable of delivering more than a couple hundred milliamps, Fig. B will burn out D5, and then proceed to damage the battery through the body diode.
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