how can I calculate the output impedance for this circuit?
In an attempt to answer my own question...
I read on one site that ZOUT = VCE/IC.
So here are my calculations, may the force be with me. (Not that I believe in the force anyway!)
Voltage feed for this circuit is 9 v. Current for this circuit is 3.8 mA.
Vce = Vcc - Vc - Ve
Vce = 9 - IcRc - IeRe
Vce = 9 - (0.0038) - (0.0038 x 2200)
Vce = 9 - 0.0038 - 8.36 = 0.63
So Vce/Ic (Output Impedance) = 0.63/.0038 =
165 ohms (This is not what I am expecting, I have missed something here).
I know there is an AC reactance of 314 ohms at 5 mHz but how do I integrate this reactance with the DC resistance?
Ah, perhaps I need Z = sq rt of DC R Squared plus AC R Squared
This would come out at 354 ohms so this is still not right.
Okay, everyone. I did my best... please can someone help...