hi,
If say the bulb was a 6volt bulb and the capacitor had been charged to say 6 volts then when the bulb was connected across the capacitor, the bulb would briefly light up and then quickly go dark.
The time it remained lit would also depend upon the value of the capacitor in micro farads.
The bulb has a resistance value, say its a 6V bulb and rated at 6 watts, [when light] the current thru the bulb would be 6W/6V = 1 amp, so using OHMS law the resistance would be R=V/I = 6V/1A =6 ohms. OK.?