jigidyjensen
New Member
When calculating the power dissipated by a npn transistor, Pq = (Vc)(Ic). Why don't we include the current in the bass as well? Why isn't it the following
Pq = (Vc)(Ic) + (Vb)(Ib)
??
Pq = (Vc)(Ic) + (Vb)(Ib)
??