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I would like to know how can i calculate base current when base is directly connected to emittor/collector?
Ir1 = 600uA Ib= 2uA
I though current would be splitted in half. But it isnt.
It was strange to me. I supposed that current would flow symetricaly in two different paths (splited in halfs). I am learning at my own, sometimes I just stare blankly into a book... Then i ask here =)
With the base connected to the collector then the emitter current is exactly the same as the collector.
With the base connected to the emitter then the transistor is turned off and does not conduct any current.