Hi,
Please could someone clear up a doubt about transistor biasing?
The "receiver" in the attachment is listening for a 1kHz square wave at 87.5 MHz FM. From the US FCC regulations, the incoming signal strength should be about 0.2 mV and 50 uA.
The MPSA18 amplifier has Vbe(on) = 0.7 VDC and hFE = 400. I used one of the on-line "voltage divider biasing" calculators, to convert the MPSA18 characteristics into the 39K/27K/3R3/560R values.
Here's what I can't see. The R1/R2 voltage divider give 4.6 VDC. If so, is a biased transistor's voltage always on? And if so, is the meagre 0.2 mV from the antenna irrelevant?
If a transistor is a current-controlled device, is the current through the potential divider more than enough to keep the MPSA18 permanently on? Should I calculate that as:
12 V / (39+27) KOhm = 180 uA?
And if so, will the 50 uA from the antenna make any difference?
How does this work? I'm missing something very basic and obvious.
Thanks a lot.
Please could someone clear up a doubt about transistor biasing?
The "receiver" in the attachment is listening for a 1kHz square wave at 87.5 MHz FM. From the US FCC regulations, the incoming signal strength should be about 0.2 mV and 50 uA.
The MPSA18 amplifier has Vbe(on) = 0.7 VDC and hFE = 400. I used one of the on-line "voltage divider biasing" calculators, to convert the MPSA18 characteristics into the 39K/27K/3R3/560R values.
Here's what I can't see. The R1/R2 voltage divider give 4.6 VDC. If so, is a biased transistor's voltage always on? And if so, is the meagre 0.2 mV from the antenna irrelevant?
If a transistor is a current-controlled device, is the current through the potential divider more than enough to keep the MPSA18 permanently on? Should I calculate that as:
12 V / (39+27) KOhm = 180 uA?
And if so, will the 50 uA from the antenna make any difference?
How does this work? I'm missing something very basic and obvious.
Thanks a lot.
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