....i think the average value looks pretty much like what it is, which is 0.096V/0.082R = 1.16 Amps.
You rightly note that the rms is virtually the same..........so really, you would say there's no point in filtering out this ripple?...since I^2.R losses will be pretty much the same whether or not it gets filtered.
Hello again,
I was still adding info to the previous post, but i'll add here instead...
We can calculate a typical setup both ways and see how much difference it makes. If you say the nominal is 1.16 amps however then what is your min and max current?
Lets just take two simple min and max, and use that for the example, then if you'd like we can come back and do it again with your numbers.
We'll say min=0.5 amps and max=1.2 amps. That looks like what it is from the graph you posted. So we'll start with that and come back again if needed. This makes the average about equal to 0.85 amps.
Ok, so first with the 0.85 amps we get t=3.52 hours. That would be applying only the nominal current level.
Next, for the min we get t=6.66 and for the max we get t=2.33 hours. So applying these for a quarter of the time and the nominal for half the time, we get a grand total of:
t=4.01 hours.
So using the min and max and nominal in this example resulted in a longer predicted run time than using just the nominal current alone. So filtering the ripple would actually reduce run time for this example. That makes some sense because filtering usually works better with high current pulses.
We could do a more explicit calculation using the waveform itself but we probably dont need to do this. If we do, we might benefit from a larger picture of the waveform itself.
So what values you want to use for min, max and nominal (average)?