What is the difference between an AND gate and a NAND gate?
The output from a NAND gate is the same as the output from an AND gate except it is inverted.
So simply add a logic inverter from a 7404 to the output of an AND gate from a 7408 like this:
As Audioguru said + anything with an N in front means the output is inverted. The same applies to NOR. It's simply an OR with an inverted output using a 7404, CD4069 etc
XNOR also follows the same logic.
The N means NOT and in Boolean logic means the opposite. i.e. what was a 1 becomes a 0 and a 0 becomes a 1 at the output.
A NOT gate simply inverts the signal. There is no such thing as an OT gate other than a buffer or a piece of wire
Yea, just add an N will make a off topic post relevant again (NOT)
By the way - having a NOT gate in adition will provide both the inverted result and the noninverted result, wich should be paid atention to in order to make complex circuits having less number of logic gates.
One thing to remember is that all of the logic functions can be implemented with a 2 Input NAND gate. Off the top of my head i forget the other gate that can be used by itself.
One thing to remember is that all of the logic functions can be implemented with a 2 Input NAND gate. Off the top of my head i forget the other gate that can be used by itself.