Thankyou sooooooooo much Len,
I do know the steady state solution for RL and RC.. but i am stuck with the differential equations like the one we figured out before.
parallel circuits are @$#@@ for me.
I feel i am bothering u a lot.Do tell me what i shud do.
i= k exp(-t/tau)
at t=0 depends om the initial conditions.
current throu inductor is zero....am i right? Yes, but don't evaluate k at this point. Wait until you find the particular function and then i = ic + ip where c = complementry, p = particular
Then make i = 0 and t = 0 to determine k
...?
2.how did u get that value for A? I think you may be misunderstanding what I meant by "A"
The particular function is ip = I/tau exp (-t/tau) integral exp(t/tau) cos wt dt where tau = L/R
let I the input be Icoswt.
for getting the particular solution from
di/dt+R/Li=RIcoswt/L
i read that Acoswt is the solution assumed for first and second order equations.
and its found by putting into the first equation and equating the coefficients on RHS and LHS....is it correct?
but then the value of A; ip = I/tau exp (-t/tau) integral exp(t/tau) cos wt dt where tau = L/R
when i equated the two sides i din get this...sheesh i think i am a dumbo. :lol: