A simple logic question

Vizier87 · Jul 22, 2014

Hi guys,

Is this correct?

Code:

case ('p'||'P'):
         digit(0xce);
         break;

Basically, what I'm trying to do is to display the same thing when I enter either a "p" or "P".

This goes like Display("PpPpP") and it goes about showing the same characters. However when used this, it doesn't work and the 7-segment display just omitted the entire character.

However, if it is like this:

Code:

case ('p'):
         digit(0xce);
         break;

It works just fine but I have to put only a small "p" in my string.

What did I miss?

Thanks.
Vizier87.

NorthGuy · Jul 22, 2014

C:

case 'p':
case 'P':
   digit(0xce);
   break;

Vizier87 · Jul 22, 2014

Thanks NG. I'll try that out when I get back. Mind telling me what's wrong with the previous one though?

NorthGuy · Jul 22, 2014

Vizier87 said:
Thanks NG. I'll try that out when I get back. Mind telling me what's wrong with the previous one though?

"||" is a boolean operation which evaluates to 0 if both operands are 0, or 1 otherwise.

'p'||'P' evaluates to 1

C:

case 'p'||'P':

is the same as:

C:

case 0x01:

Vizier87 · Jul 22, 2014

NorthGuy said:
"||" is a boolean operation which evaluates to 0 if both operands are 0, or 1 otherwise.

'p'||'P' evaluates to 1

C:

case 'p'||'P':

is the same as:

C:

case 0x01:

I see. I thought the || is only an OR logical operator?

NorthGuy · Jul 22, 2014

Vizier87 said:
I see. I thought the || is only an OR logical operator?

Yes, that's what logical or does - 0 id both operands are 0, 1 otherwise. C doesn't follow English langauge, it has its own rules.

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