To measure the output of your AC/DC adapter at its full rated output of 5V/1A then simply use Ohm's Law to calculate a load resistor:
5V/1A= 5 ohms. The power in the resistor will be 5V x 1A= 5W.
5 ohms is not a standard value so use two 10 ohms/5W resistors in parallel.
Hi AG, i couldn find a 5W resistor in my collection, but i got a 1/4W(or 1/2W) resistors. So experimented with it, by momentarily(for few secs) connecting the multimeter (and Resistor) to the adapter.
For 10ohms load, i got the voltage o/p as 5.07V i.e., (500mA).
For 100ohms load, i got it as 5.32V (50mA).
Since i used 1/4W resistors, i felt an huge heat when i touched the resistor after that.
This means that: as drawn current decreases, the o/p voltage increases.
I dont know the max current drawn by the iPod, but it would probably be around 500mA(not sure though).
But, is there anyway i can find the current drawn by the iPod(i mean by calc the iPod's res(i.e., Load))?
I sense that there will be no prob in using this USB Adapter. TY