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hi, is there anyone that can simplify this boolean expression algebraically?
PG'CK + PGCK' + PGCK
i know how to simplify some expressions but this on im real stuck on :?
Changing it to PC(G'K+GK'+GK) is about as far as i can get really, any help would be appreciated, thnx
well think about it... the term in parentheses is true if GK=01, 10, or 11... so in other words it is true if EITHER of G and K are true. so it should reduce to just (G+K)
if I add another set of brackets and swap the order of the last two terms around ...
PC(G'K+GK'+GK)
PC((G'K+GK)+GK')
is that implying that G is a 'don't care' ?
you can do the same thing with K. simply put the GK term in there twice (doesn't change anything)... then you end up with ((G'K+GK)+(GK+GK')) which makes G a don't care for the first expression, and K a don't care for the second... in other words the whole thing is (K+G) like i said before.
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