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MAN U ARE REALLY VERY CONCEPTUALLY ..tkbits said:0 ^ 0 is undefined.
For n > 0, 0 ^ n = 0.
For x not 0, x ^ 0 = 1.
I would have thought so, but if you set x = -1 in the series I posted above, 0^0 = 1.tkbits said:0 ^ 0 is undefined.
For n > 0, 0 ^ n = 0.
For x not 0, x ^ 0 = 1.
I did not use the 0^1/0^1 = 0^(n-n) proof. I used the series posted above which does not have any division by zero.wschroeder said:Division by 0 is undefined for real numbers. If we use the example 0^1/0^1 = 0^(n-n) you have a problem to declare or prove 0^0 = 1.