ChristianCMcKay
New Member
Okay, so I've been checking a lot of capacitors lately. I've been trying to find out exactly what the capacitance was. So here was the method I was going about to do this.
First I solve for Xc
I know that Xc = 1/(2*3.14*f*C)
So then I set up a low pass filter. I then use the forumula
Vpp = (Xc/[R + Xc])*Vin
So I measure to see if I'm relatively close. In one case, I wasn't. Way off. I wanted to calculate to see what the capacitance changed to. I'm also really not so great at changing formulas to solve for something else. So what I was trying to do was...
Solve Vpp = (Xc/[R + Xc])*Vin for Xc
When I got Xc, I would then try to...
Solve Xc = 1/(2*3.14*f*C) for C
Can anyone help me with the last part of this?
First I solve for Xc
I know that Xc = 1/(2*3.14*f*C)
So then I set up a low pass filter. I then use the forumula
Vpp = (Xc/[R + Xc])*Vin
So I measure to see if I'm relatively close. In one case, I wasn't. Way off. I wanted to calculate to see what the capacitance changed to. I'm also really not so great at changing formulas to solve for something else. So what I was trying to do was...
Solve Vpp = (Xc/[R + Xc])*Vin for Xc
When I got Xc, I would then try to...
Solve Xc = 1/(2*3.14*f*C) for C
Can anyone help me with the last part of this?