PIC C18 Compiler Issues: Pointers, Function Prototypes - Electronic Circuits Projects Diagrams Free

Fred.Amoson · 2nd April 2008, 11:50 AM

I am working on a new project with the C18 compiler. For the most part things are going well, but I have ran into a few glitches that I cannot figure out.

One small thing that I can't figure out is that everytime I compile I get:

"Warning [2058] call of function without prototype"

Even though the function being called does have a prototype. For instance, on the line where the function initializeLCD() is called, it gives me that warning, however in my header file I have the line:

void initializeLCD();

and the header file is included in the project. Anyone know what the deal with this is?

Also, I can't seem to get pointers working in C18. I am trying to have a globally addressable array of text that I can read to or write from any function. Any attempt at this has failed. Here is a snippet of where I define my variables:

Code:

char dataArray[] = "Text Array";
char *pData;

void main (void)
{	
	OSCCON = 0b01110000; //8MHz Clock
	pData = dataArray;

Then in a later function I set:

pData = "Testing";

But when I try to pull up pData[0] I get a 0 instead of a T. Also, dataArray is still equal to text array. I've tried a combination of & and * but I just can't seem to get it. Any help would be greatly appreciated!

eng1 · 2nd April 2008, 12:31 PM

Quote:

Originally Posted by Fred.Amoson

I am working on a new project with the C18 compiler. For the most part things are going well, but I have ran into a few glitches that I cannot figure out.

One small thing that I can't figure out is that everytime I compile I get:

"Warning [2058] call of function without prototype"

Even though the function being called does have a prototype. For instance, on the line where the function initializeLCD() is called, it gives me that warning, however in my header file I have the line:

void initializeLCD();

and the header file is included in the project. Anyone know what the deal with this is?

Use the 'void' type when you declare functions with no arguments; that should fix the problem.

Code:

void initializeLCD(void);

Fred.Amoson · 2nd April 2008, 01:27 PM

Thanks, that fixed the first problem!

Papabravo · 2nd April 2008, 09:40 PM

Quote:

Originally Posted by Fred.Amoson

...
Also, I can't seem to get pointers working in C18. I am trying to have a globally addressable array of text that I can read to or write from any function. Any attempt at this has failed. Here is a snippet of where I define my variables:

Code:

char dataArray[] = "Text Array";
char *pData;

void main (void)
{	
	OSCCON = 0b01110000; //8MHz Clock
	pData = dataArray;

Then in a later function I set:

pData = "Testing";

But when I try to pull up pData[0] I get a 0 instead of a T. Also, dataArray is still equal to text array. I've tried a combination of & and * but I just can't seem to get it. Any help would be greatly appreciated!

It's a Ha'va'd architecture man. There are two memory types. Program memory is as wide as the instruction word and techniques vary as to how a "constant character string" is packed into program memory. Then there is data memory which is as wide as the registers, typically 8 bits. Now a pointer to a constant character string in Program memory is a very different animal from a pointer to a character string in data memory.

I would look for keywords that help the compiler determine what kind of memory the pointer is pointing at.

I went to Princeton and we treat all memory the same. We don't have such problems.

Fred.Amoson · 3rd April 2008, 02:51 AM

Thanks for the info Papabravo, that helps a lot, I will post back when I figure it out!

Pommie · 3rd April 2008, 03:04 AM

Pointers on a pic are one of the most confusing things I've come across. The only way to get a string from ROM into RAM is to copy it manually.

Here's my understanding of how to manipulate strings.

Code:

ram char dataArray[20]="Test Data";
ram char *pData;

//copy string from rom to ram.
void SetString(ram char* RamString,rom char* RomString){
    do{
        *RamString++=*RomString;
    }while(*RomString++!=0);
}

//in main you can then have,
static rom char HW[]="Hello world";

//You can then do,
    SetString(dataArray,(rom char*) "Hello World");
//or
    SetString(dataArray,HW);

//you can also do,
    pData=dataArray;
    chr=*pData;
    SetString(pData,(rom char*) "Somert else.");

You have to remember that the compiler wants (has) to treat all strings as constants and stick them in ROM.

Mike.

Papabravo · 3rd April 2008, 09:25 AM

So are "ram" and "rom" the keyword qualifiers in the C18 compiler?

Papabravo · 3rd April 2008, 09:27 AM

Quote:

Originally Posted by Fred.Amoson

Thanks for the info Papabravo, that helps a lot, I will post back when I figure it out!

No problem -- glad to be of assistance.
Good Luck

Pommie · 3rd April 2008, 09:47 AM

Quote:

Originally Posted by Papabravo

So are "ram" and "rom" the keyword qualifiers in the C18 compiler?

Kind of, there are actually four different types of pointer, and there not interchangeable.
near rom
far rom
near ram
far ram

But generally you can just use rom and ram.

Mike.

Fred.Amoson · 13th April 2008, 12:45 AM

Thanks a lot Pommie, your code has really saved me a lot of time. I would have never figured that out.

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2nd April 2008, 11:50 AM	#1
Fred.Amoson	PIC C18 Compiler Issues: Pointers, Function Prototypes I am working on a new project with the C18 compiler. For the most part things are going well, but I have ran into a few glitches that I cannot figure out. One small thing that I can't figure out is that everytime I compile I get: "Warning [2058] call of function without prototype" Even though the function being called does have a prototype. For instance, on the line where the function initializeLCD() is called, it gives me that warning, however in my header file I have the line: void initializeLCD(); and the header file is included in the project. Anyone know what the deal with this is? Also, I can't seem to get pointers working in C18. I am trying to have a globally addressable array of text that I can read to or write from any function. Any attempt at this has failed. Here is a snippet of where I define my variables: Code: char dataArray[] = "Text Array"; char pData; void main (void) { OSCCON = 0b01110000; //8MHz Clock pData = dataArray; Then in a later function I set: pData = "Testing"; But when I try to pull up pData[0] I get a 0 instead of a T. Also, dataArray is still equal to text array. I've tried a combination of & and but I just can't seem to get it. Any help would be greatly appreciated!

2nd April 2008, 01:27 PM	#3
Fred.Amoson	Thanks, that fixed the first problem!

3rd April 2008, 02:51 AM	#5
Fred.Amoson	Thanks for the info Papabravo, that helps a lot, I will post back when I figure it out!

3rd April 2008, 09:25 AM	#7
Papabravo	So are "ram" and "rom" the keyword qualifiers in the C18 compiler? __________________ We never have time to do it right; but we always have time to do it over.

13th April 2008, 12:45 AM	#10
Fred.Amoson	Thanks a lot Pommie, your code has really saved me a lot of time. I would have never figured that out.