If I wanted to drive 2 or 3 of these modules in parallel, what kind of driver would I need?
thanks
thanks
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Ok, so Qg is 2750nC. with 1A and one module, it would take 2750nS to switch? And with 9A driver, 2750nC, it would be 305nS? and then with 3 in parallel, 9A it would be 916nS (1uS)?If you check out the spec for Qg you can get an idea of the time to switch (in ns) with 1 amp of gate current. More gate current faster switch time. So say a 9 amp driver and 3 in parallel. This would get you a switch time of around 1 us.
There is a lot of power dissipated in the module when it is half on and half off. That's why it is important to know how often it will be switching.
I was thinking 20khz, just to be outside the audible frequency rangeHow fast do you want to drive? 60hz or 100khz? It looks like you need 10 volts for the gate.
Ok, so Qg is 2750nC. with 1A and one module, it would take 2750nS to switch? And with 9A driver, 2750nC, it would be 305nS? and then with 3 in parallel, 9A it would be 916nS (1uS)?
Will dedicated gate drivers ensure that all my MOSFETs switch on and off together? I am changing my plan to use 5 or 6 smaller MOSFETs and I have read that trying to get them all to turn on/off at the same time is tricky business.You can use 3 gate drive ICs.
There are some application notes on (not connecting gates together). The oscillation that may happen is very fast and you might not see it. and Three grate drivers will increase your turn on/off speed.
What about the turn on delay time and rise time? Are those in addition to this thumb rule?Right you are.
Are you sure you need so much power? Maybe so if you are going to do a 400HP racer?
Good thing I have a scope, but not too experienced at using it. It's a tektronix 2440(?) I believe, from the early 90's. I have a 10X probe; is there any voltage above which I shouldn't use it? I've read connecting it to mains 120V is a no-no. I'm not using a H-bridge; I have seen in other schematics a 10ohm resistor used as a gate resistor; is this a good value? how do you decide a gate resistor value?Probably a good idea to do a lower power prototype. The smoke from a $2 FET smells about the same as a $1000 one. It's a complex project and some things are bound to go wrong along the way. Your right, most of the principals are the same.
Find a driver that is big enough to drive all your parallel FETS at a good rate (say less than a µs). The gate resistor helps reduce "ringing" as the FET switches. The down side is that it reduces the available current to turn the FET on and off. There should not be a problem driving several FETs from one good driver but you do need to be careful to keep the traces short from driver to gate and source back to driver. One other thing to consider when looking for a driver is "shoot thru". FETs always seem to turn on faster than they turn off. So if you have a H-Bridge configuration where the FETs clamp the inductive kick it is easy to have both FETs on the same side of the bridge on at the same time for a short time. Some drivers have a delay that can be set to prevent this. You can also "play" with the gate drive design to reduce this but it's nice to know you can't have both of them on at the same time. It's nice to have a scope to look at things like this since in real life they never seem to be as fast as the data-sheet.
In all 10's of times I've looked over the datasheet, I missed that (gate resistor) every time! Thanks! Do you think that means they determined that 2.7Ω is the minimum required to prevent ringing?It's really not so important. They never behave like the spec. sheet when you get them in the circuit anyway. The data sheet will usually show the switch times with a gate resistor and 10 volts on the gate. (There is little advantage to a gate voltage over 10 volts.) Since Qg is switch time with a constant 1 amp I usually just use half the peak gate current. Ton=1/2 I gate X Qg. So in your case they spec a 2.7 ohm gate resistor. So 3.7 amps peak/2= 1.85. Qg is 170/1.85=92ns. Compare this with there switch times with the 2.7 ohm resistor of 92 ns. Pretty close I guess. When you get it on a board with traces and stuff it may be twice as slow - enter the scope. I would use a single driver and say 7.5 ohm gate resistors for each FET.
Speaking of gate drivers. I'm guessing you are building a H-Bridge or a Half-Bridge. This will require a high side driver as well as a low side driver. So you might want to look for at least 1/2 bridge drivers.
PS. your scope with 10X probes should work at your voltages.
is this (the 1/2 gate current) your own thumb rule for accounting for real world losses and the circuit board, or is there a mathematical reason for this?I usually just use half the peak gate current. Ton=1/2 I gate X Qg.