What is this part? Is it ferrite?

AlainB

Member

• Mar 10, 2009

• #1

Hi,

I am talking about the one in the top. The other is a 1N4004 diode for size comparison.

Well this part is not a diode and offer no resistance noticeable with my multimeter.

What is it (a ferrite?) and wy is this part used in a circuit. What is his purpose?

Thanks!

Alain

 

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Last edited: Mar 10, 2009

OutToLunch

New Member

• Mar 10, 2009

• #2

ferrite beads are just tiny inductors and are used as filter elements

 

DirtyLude

Well-Known Member

• Mar 10, 2009

• #3

Looks like one to me.

EDIT: Oh yeah. purpose. Like mentioned, filters. I've used them for power filters for sensitive devices, like RF transceivers.

 

Last edited: Mar 10, 2009

U

Ubergeek63

Well-Known Member

• Mar 10, 2009

• #4

actually they tend to be more dissipative than inductive at their intended frequencies.

Dan

 

crutschow

Well-Known Member

Most Helpful Member

• Mar 10, 2009

• #5

Ubergeek63 said:

actually they tend to be more dissipative than inductive at their intended frequencies.

Click to expand...

Yes. They act like lossy inductors and are used to attenuate high frequency signals in digital and RF circuits. You don't want a pure inductance for such a filter since that would tend to form resonances with any capacitance in the system.

 

Hero999

Banned

• Mar 10, 2009

• #6

Yes, they electrically look like a transformer with a resistor connected across the secondary and are resistive above a certain frequency.

 

Boncuk

New Member

• Mar 10, 2009

• #7

The bottom picture shows a diode, which I identified by the cathode ring at the right hand side.

Boncuk