Richardcavell
Member
Hi, everyone. I have an Atmel AVR microchip that has a RESET pin. One is told to supply current of approx +5 volts to it at all times. One is also advised to supply that current through a "pull up" resistor of at least 2.2 kohms to prevent a too-large current from going through the microchip.
1. "Pull-up" means simply that the resistor is connected to the positive rail, right?
2. If this is true, then it's not really the resistor that pulls up the voltage, but the positive rail itself, correct?
3. If there were nothing attached to the pin, it would be "floating". I recognize that this means that there is no connection on one side to establish its voltage, but wouldn't any electric potential in the remaining part of the "circuit" simply quickly drain?
4. The 2.2k resistor and the AVR chip will then form a voltage divider, correct?
5. Can I assume that the resistance of the chip is sufficiently large that the 2.2k resistor is relatively trivial?
6. If not, then wouldn't the 2.2k resistor drop sufficient voltage that I can no longer rely on the input to the reset pin being 5 volts?
1. "Pull-up" means simply that the resistor is connected to the positive rail, right?
2. If this is true, then it's not really the resistor that pulls up the voltage, but the positive rail itself, correct?
3. If there were nothing attached to the pin, it would be "floating". I recognize that this means that there is no connection on one side to establish its voltage, but wouldn't any electric potential in the remaining part of the "circuit" simply quickly drain?
4. The 2.2k resistor and the AVR chip will then form a voltage divider, correct?
5. Can I assume that the resistance of the chip is sufficiently large that the 2.2k resistor is relatively trivial?
6. If not, then wouldn't the 2.2k resistor drop sufficient voltage that I can no longer rely on the input to the reset pin being 5 volts?