TotalMadness
New Member
Can anyone tell me what the difference is or how a capacitor will function when one is 40v and 100µF, and the other is 40v and 1000µF?
Thanks
Thanks
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The µF value is the capacitance. 1000µF can hold 10 times as much charge as a 100µF. The 40V is the maximum voltage rating of the capacitor, and should always be higher than the highest voltage it will see in your circuit.
I find it curious the way you like to generate or expand definitions of common electrical terms in a way that nobody else uses and is contrary to common usage. Obviously you delight in trying to confuse the neophytes out there.kpatz,
What you really mean to say is that the 1000µf cap will store 10 times the electrical energy of a 100µf cap, when both are at the same voltage. The net stored charge of any capacitor at any voltage is zero. That is because any charge that is accumulated on one plate is depleted by an equal amount on the opposite plate.
crutschow said:but you are a minority of one
1000uF is 10 times 100uF so it will filter 10 times better.
To the original poster, how it will behave depends completely on the circuit it is in!
Visitors want simple answers to basic questions. Not lot's of complicated stuff.Cheers
Ratchit, do not drag your other thread onto this simple question.
Also note the difference between net charge and total charge.
1 electron and 1 proton is a net charge of 0. 20 electrons and 20 protons is a net charge of 0.
The 2nd option has 20 times more charge than the first.
Energy is related to charge.
Let go of this point that you seem to enjoy arguing way too much.
I find it curious the way you like to generate or expand definitions of common electrical terms in a way that nobody else uses and is contrary to common usage. Obviously you delight in trying to confuse the neophytes out there.
But when engineers (not lawyers) refer to charge on a capacitor they are not referring to net charge, they are referring to accumulated charge on one of the plates.
You can, of course, continue to keep referring to the net charge on a capacitor when someone mentions capacitor charge, but you are a minority of one in that interpretation.
Keep it simple Ratch. Otherwise you scare the OP away. Lost to ETO forever.
Visitors want simple answers to basic questions. Not lot's of complicated stuff.
I could turn an ordinary piece of Copper Wire into a complicated discussion if I wanted to: Production processes and all. Temperatures. Draw length. Copper strength. Copper cooling ability VS Aluminum. And so on.
Of course lawyers don't get involved with capacitors much. I was being facetious, since all your posts have a legalistic tenor to the prose, but I guess you didn't pick up on that, or chose not to.I don't think lawyers get involved with capacitors very much. Can you find any documentation that says a charge on a capacitor refers to the imbalance of coulombs between the two plates? That is, the accumulation of charge on one plate, AND the depletion of charge on the opposite place. It is true, but can you find documentation?
If you agree that the charge on a capacitor is the accumulation of charge on one plate and the depletion on the other, then why do you want me to search for documentation for that? Are you implying that you know of no documentation to that effect?
If you can find a good correct description of how a cap works without spending too much time searching, I would appreciate it.
V(capacitor) = 1/F*1mA*T, where T is the time elapsed starting from when the current was applied. Now, you see if the farad ("F" in this example) is bigger, then the voltage is lower for the same current and time. And thus, the ability of the capacitor to store the charge (the "capacity") is increased for more farads.
Thanks, I understand now.