Voltage Drop measurement using Digital Multimeter in a 5A live circuit

Consider the below circuit with 28V supply and electronic load set at 5A Constant Current mode.

What voltage drop would I expect when I connect a digital multimeter between A & B ?
V(AB1)= V(R6)+V(R8)+V(R9)


What voltage drop would I expect when I connect a digital multimeter between C & D ?
V(CD1)= V(R7)+V(R8)+V(R10)

Consider the second circuit.

What voltage would I expect when I connect a multimeter between A & B ?
V(AB2)= V(R6)+V(R8)+V(R9)


What voltage would I expect when I connect a multimeter between C & D ?
V(CD2)= V(R8)

Am I right ? And V(AB2)>V(AB1)

Much better wording, and you are still correct.

There was no reason to re-post the whole thing, surely?

JimB