It depends upon the particular configuration. For example, consider a common emitter circuit used as an amplifier with a pair of resistors acting as a voltage divider (R1 to Vcc & R2 to gnd) to set the base voltage, a resistor between the emitter & gnd and a resistor from the collector to the Vcc.
For a high gain transistor, the procedure is:-
Calculate the base voltage Vb = Vcc * R2/(R1 + R2).
For a silicon transistor, subtract 0.7V from this figure. This gives the emitter voltage Ve.
Calculate the emitter current using Ohm's law.
For a high gain transistor, the collector current is almost equal to the emitter current so assume that Ic = Ie, thus calculate the voltage across the collector resistor Ic * Rc. If this figure is less than Vcc - Ve - 1 then the transistor is in the active region. The collector voltage can then be calculated by subtracting this figure from Vcc.
This procedure gives a good approximation to the voltages and currents.
For a low gain transistor it is more complicated as you must consider the transistor's gain.