So true.I spread chaos where ever I am.
Why create such a complex circuit????
Yellow LEDs don't drop 3.8v.
30mA per string is too high. LEDs are designed for 17mA to 20mA.
A 555 on 15v can deliver 400mA via a simple transistor buffer.
18R is far too low.
Add a sw across the collector-emitter to create FULLY ON.
So true.
I have been a teacher of electronics for more than 30 years.
You have made so many mistakes in the above reply.
Firstly, you are not simulating a LED circuit. You have specified a yellow LED as 3.8v. This is not true.
.The LED's are 5mm, 3.8v and 30mA.
Secondly, you have specified the dropper resistor as 18R.
It is very dangerous to use a resistor less than 100R as LEDs have a wide margin for their "characteristic voltage-drop" and any variations will be easily "eaten" by the small voltage you have allowed by the 18R.
I use 20,000 LEDs at a time and for long term performance, most common LEDs are best run with a current of about 17mA to 20mA. 25mA shortens their life and 30mA is damaging.
You can see my website has dozens of circuits driving a set of LEDs via a 555 and a buffer transistor.
You circuit is grossly over-designed and providing ill-information.
The LED's are 5mm, 3.8v and 30mA.
5mm LEDS are not rated at 10W.
You have specified a 15v DC plug-pack. Do you realise the no-load output voltage of these devices is about 5v higher than 15v. You are simply zenering the LEDs with the supply voltage and they are sure to be damaged.
It puts out the nominal voltage at nominal current. No matter if the LEDs are blinking or steady on - the current will be the same as soon as power is required.
The LED's are 5mm, 3.8v and 30mA.
You are going back to the very point that I tried to tell you was a dangerous condition.And an array of 6x6 with 1ohm resistors
We use cookies and similar technologies for the following purposes:
Do you accept cookies and these technologies?
We use cookies and similar technologies for the following purposes:
Do you accept cookies and these technologies?