Hi planty,
there are no T1 - T4, but TP1 - TP4. Those are terminals to connect supply voltage and output to the world.
It's quite clear you don't see much reaction of the circuit. If wired correctly the monoflop's time out period is exactly 1.099ms or 0.001099seconds. (R1=1K and C1=1µF) Considering tolerance in capacitance this period might even be shorter.
You can wire an LED (anode) to the output pin (3) in series with a current limiting resistor to ground. The LED is lit as long as the output is active (high), but you won't see and 1ms pulse.
Calculate the resistor like this: R(Ω)=((+UB(V)-Uf(A))/If, where +UB is the supply voltage, Uf is LED forward voltage and If is LED current.
Example: red LED (Uf=1.8V, If=20mA), +UB=12V, put into the formula:
(12-1.8)/0.02=510Ω. 510Ω is not contained in the E-24 restance row, so the next suitable value would be 560Ω. (This will result in an LED forward current of 18.2mA with a negligable loss of brightness.) Never use a lower resistance value than calculated.
Here are values for R1 and C2 for a reasonable time period of 2.427 seconds.
R1=470K, C2=4.7µF. To almost double the time out use R1=820K.
Boncuk