I'm not sure how much would count as "doing it all for you", but it would probably be ok to point out to you that a bipolar transistor's collector acts as a
current source (or a current sink if you prefer), where the current passed is basically determined by that which goes through the emitter. It's close enough that for most purposes you treat it as equal even if it's not (IE=IC+IB, but IB is tiny).
If for instance, there is a resistance from the emitter to ground, then you can work out the current from the voltage across that resistance.
I trust you know how to work out the emitter voltage (or voltage swing, even), yeah?
Naturally, Ohm's law also applies to resistances driven by current sources rather than voltage sources. A common-emitter amplifier will have a resistor (ISTR maybe seeing other things used in their place occasionally but I forget) from collector to Vcc. You've presumably noticed that, right? Hopefully you have a good sense of how a current source behaves too- if not, you need to acquaint yourself with them a bit better.
Now, just join the dots. It really isn't that hard. Even I can do it
Naturally there is more in a transistor amp than just this, but that's the details you've probably missed.
Working it out for "small signals" rather than absolute quantities is mostly the same deal.