There is a question, probably elementary but im new at this, ? Is Design, draw, and wire a 5 input NAND circuit using one 2 input OR gate, one 2 input NAND gate , and one 4 input NAND gate.
Ive been drawing this circuit for a couple hours and have no idea, I know a 5 input NAND gate will only go low if all inputs are high, but with the 2 input NAND in there going low with its inputs high, I cant solve how to build this circuit, please help. Thank you.
As this looks like a homework question just giving you the answer will not teach you to understand. So here is a tip. Apply DeMorgan's Theorem to the 2 input OR gate. The result will be a 2 input AND gate for NEGATIVE logic. The solution I came up with results in a 6 input NAND gate but you could just tie 2 inputs together or tie one input high.
1)At first I tried to take the OR + NAND and make some thing to go ahead the 4-NAND. In 20 seconds I could not see it.
2)What do we have? 4 input NAND + 2 input NAND
>>To make a 6 input NAND we would need (the 4 input NAND) OR (the 2 input NAND).
Thanks for the replys, yes this is a lab question where we are supposed to draw a schematic and the build it out and test on a breadboard. I still cant seem to make anything that will act like a 5 input NAND from these components, Im not sure how the OR gate should have any relevance in the circuit, tying the legs together makes it irrelevant, tying the 2 legs of the 2 input NAND together makes an inverter, the closest thing I can come up is different combinations where all 5 inputs are high will result in a low output, but there will be other situations as well that give a low output.
I see it now, thanks Mike. I get myself confused with active and unactive outputs, i build it that way a few times im sure and when I looked at it , i thought well that wont work. Thinking too hard. Thanks again