Hi there,
I'm not sure I should have started a new thread here as it's similar to the " constant 5v regulator " but I did not wish to confuse things.
I too am new to the Forum and electronics so hi and sorry for any silly questions.
Here's my problem -
I have rigged up a solar phone charging setup for a forthcoming backpacking trip. I am carrying all my food and equipment for 18 days, therefore weight is a premium.
I need a reliable power source as I will be navigating using digital mapping.
So far it consists of a 12v 6.5w flexible solar panel charging a MiLi power crystal 2000mAh Lithium-Polymer Battery (5v 1A max in/out), through a 12v - 5v phone charger.
My phone stays connected to the battery so is constantly charged, with the battery there for backup.
I reallise there is power wastage here but my thinking was a large panel would provide more juice in low light.
As this system stands, it works well in good conditions but in low light the voltage drops to between 6-10v and as the charger needs 12v, no power is available.
My question is how can I utilise this low light power, I was thinking maybe just using a 6v diode but this is probable way too simplistic.
I would appreciate any help available.
Thanks in advance,
Paul
I'm not sure I should have started a new thread here as it's similar to the " constant 5v regulator " but I did not wish to confuse things.
I too am new to the Forum and electronics so hi and sorry for any silly questions.
Here's my problem -
I have rigged up a solar phone charging setup for a forthcoming backpacking trip. I am carrying all my food and equipment for 18 days, therefore weight is a premium.
I need a reliable power source as I will be navigating using digital mapping.
So far it consists of a 12v 6.5w flexible solar panel charging a MiLi power crystal 2000mAh Lithium-Polymer Battery (5v 1A max in/out), through a 12v - 5v phone charger.
My phone stays connected to the battery so is constantly charged, with the battery there for backup.
I reallise there is power wastage here but my thinking was a large panel would provide more juice in low light.
As this system stands, it works well in good conditions but in low light the voltage drops to between 6-10v and as the charger needs 12v, no power is available.
My question is how can I utilise this low light power, I was thinking maybe just using a 6v diode but this is probable way too simplistic.
I would appreciate any help available.
Thanks in advance,
Paul