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SLA battery charger

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TRexall

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Is there a simple circuit to charge SLA batteries 4.5 AH without getting too complicated?
Most of the circuits Ive seen have difficult to get parts ...I do have some 2N3725s(NPN) transistors tho would they work?
 
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And of course, you can go to one of my favorite Ca stores.
**broken link removed**
 
Thanks for the link..as it happens I do have alot of old parts to sift thru.
but the parts being old and the markings faded its not easy to tell what your looking at sometimes..:)
 
Also there is the danger of over-gassing the battery and blowing it up...maybe I will just buy the ready made one:D
 
difficult to get parts
Which parts? Most parts have substitutes that you can find anywhere. Tell us what you need.

See if your 2N3725s contain enough gold to sell to a recycler. Not particularly stellar performers in 2008. :eek:
 
I did manage to find the right parts for the astable multivibrator circuit..works beautifully now..;)
I guess I should invest in a good cross reference..as I had never heard of a BC-547.
I didn't know know you could salvage the gold off old transistors..maybe I should go prospecting:)
 
General purpose small signal transistors come in a lot of families, but the BC 547 and its close relatives are usually a good match for 2N3904/2N3906 and their close relatives. Fortunately the families are groped on one data sheet, so you only need a few data sheets.

I'm told that old transistors and ICs that were made when the US gold market was locked at $35 per ounce (iirc, before about 1975) can contain some salvageable gold if you know the right people. Unfortunately I don't know the right people. :(
 
I've got a solution for you! :)

It may be more simple than you wanted but it would work.

So get yourself a power supply that provides 12V (or battery max charge limit), then find a resistor that will be able to to limit the charge current to a level your power supply can handle.

Thats it, the resistor will prevent over current conditions when charging a discharged battery. then as the battery potential rises as it is charged the current will naturaly drop off to zero when the battery potential is equal to the power supply. An ammeter could be used as an indication of charge status.
 
I'd just connect it to a wall wart with add a comparator to turn it off when the voltage exceeds 13.8V.
 
I am a little confused here..the half-wave power supplly has 2 resistors called 1R8...is that 1 ohm?...I noticed they were in parrallel..sorry for being ignorant:)
 
1R8 = 1.8Ω and since there are 2 in parallel, the total resistance is 0.9Ω.
It is quite common to use R, K or M in place of the decimal in resistor values. So a 4.7KΩ resistor could be written as 4K7 and a 3.9MΩ as 3M9. It saves a character and eliminates errors after multiple photocopies of the schematic make the dots disappear. ;)
 
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Thanks for the clarification..I often add resistors in series to get the values I don"t have.
Would that resistor pair have to be point 9 ohms?..I do have a nice 1 ohm 5 watt resistor that might work
 
The 1Ω resistor will work fine. You'll just get 10% less charging current. To get 0.909Ω you could put a 10Ω 1/2W resistor in parallel with your 1Ω 5W one but I wouldn't bother as it is close enough.
 
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Well thanks for the help..Im going to consider all these suggestions and may end up digging out that old EPSON power transformer I have;)
 
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