Hi Steve,
I looked at your query, and had a little think.
Ive drawn a suggestion for you,
and heres a brief few words as to how i think
it would operate.
The circuit is drawn at rest, and as you can see,
the positive conection has nowhere to go, the press
button is open, and the reed switches are both open.
The motor driven piece is positioned to obscure the
light from light No1 although light No1 is not lit,
nor is Light No 2.
The activator presses the press button, and the motor
moves, both lights light, both reed switches operate,
and the transistor delivers a LOW to the moter sensor.
The activator releases the press button, the motor
continues, reed switch No1 is now held by current
through 'S' light sensor No1.
The motor reaches light No2 and obscures it, causing
reed switch No2 to open, this causes the transistor
to deliver a HI to the motor sensor, and causes the
light No2 to go out, the resistor across the light
may not be needed, it is to ensure a low at the
transistor output when the light goes out.
The motor then goes into reverse, and would not obscure
light No2 any more, but the lamp will not light cos the
reed switch is open.
The motor then runs back to its start position, and
obscures light No1, which causes the first reed switch
to open, and the circuit is then at rest.
I hope this meets with your approval,
if the motor logic can be easily reversed at the motor,
then the transistor may not be needed at all,
in which case the circuit would be quite simple
to construct.
Best of luck, John