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self or mutual induction question..

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http://i28.tinypic.com/ng7ny9.jpg
i was told that the two selonoid are mixed with one another.
regarding A:
why they use only one flux

why arent they summing both flux?

regarding C:
why are we find the L of selonoid B
and then do e=-L5

why we use mutual induction here
what is wrong with this way?
 
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skyhawk

New Member
i was told that the two selonoid are mixed with one another.
regarding A:
why they use only one flux

why arent they summing both flux?
Mutual inductance results from the flux through a coil produced by the field from a second coil.

Self inductance results from the flux through a coil produced by the field from the same coil.

The problem states the fluxes produced by the field from coil A in coil A and in coil B respectively.

The flux through coil A gives rise to the self inductance of A and the flux through coil B gives rise to the mutual inductance.
 

skyhawk

New Member
regarding C
why are we using the mutual induction
why arent we using the self inductance of coil B
??
Because it asks for the emf in coil B caused by the change in current in coil A (the other coil).

Self inductance relates the emf in a coil caused by a change in current in the same coil.
 
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