I am not sure if this is what you are asking... but the way a ADC works is related to the resolution of the ADC. If you have an 8-bit ADC it means that for a range of voltages from 0 to your reference Voltage, you will only have 256 numbers (from 0-255)
What I mean by this is that if your reference voltage is 5V then 0V is going to be 0, and 5V is going to be 255. That said then you know that 5V/255 will give you a resolution of 0.0196V (~0.2V). This means that each change of 0.2V on your ADC input will reflect in higher conversion.
Then
0V will be 0
0.0196V will be 1
0.0392V will be 2
0.0588V will be 4.....
2.4901V will be 127 (middle point)....
5V will be 255
The higher the resolution the smaller the voltage steps. So if you use a 10-Bit ADC you will have 1024 different numbers, and a 12-bit ADC will have 4096 so each step will be of 1.22mV with a 5V reference.
So now that you know what numbers you are getting and how, then you have to find a logic way to relate them to the EEPROM address that you want. And read it.. now that is upto you to find the correlation.
Ivancho