Continue to Site

Welcome to our site!

Electro Tech is an online community (with over 170,000 members) who enjoy talking about and building electronic circuits, projects and gadgets. To participate you need to register. Registration is free. Click here to register now.

  • Welcome to our site! Electro Tech is an online community (with over 170,000 members) who enjoy talking about and building electronic circuits, projects and gadgets. To participate you need to register. Registration is free. Click here to register now.

Question about Op Amp Substitution

Status
Not open for further replies.

woodturner550

New Member
I don't have a LM6132/LM6134 for this project. I am wondering about substituting LM6142. From looking at the datasheet (to a newbe) it looks like the main thing that I have to do is make the Op Amp exactly a doubler of the signal from the temperature sensor. Other than that it looks like it should work. So the LM6134,CMRR 100 dB, Gain 100 dB with RL = 10k/ LM6142 CMRR 107dB, Gain 108dB with RL = 10k(see attachments). Notice the table link in the doc.

Can this be done? Should it be done? What is the formula to calculate this? Is it as sinple as 100 db/10K= ohms per db, and 108 db/10K= ohms per db?


Thanks

woodturner550
 

Attachments

  • Two chip digital Thermometer.wps.doc
    533.7 KB · Views: 408
  • LM6142BIM 17 MHz Rail-to-Rail Input-Output Operational Amplifiers.pdf
    865.3 KB · Views: 205
  • LM6132 - LM6134 Dual and Quad low power 10MHz Rail-to-Rail.pdf
    807.4 KB · Views: 193
Firstly you are using the op amp in such a simple configuration, that most of the characteristics of the op amp will not matter. Your gain (in the config in your circuit) is 1 + Rf/RI where Rf = Ri = 10k, so your gain is 2 (pretty much regardless of the op amp's internal characteristics). The 100dB gain is the internal gain of the amp, but you are reducing the overall gain (to 2) using external feedback resistors, so this characteristic of the op amp does not matter

In your configuration, the only parameter that will affect the performance of your circuit is the input offset voltage (this will add/subtract a dc voltage to the one your are measuring implying a temperature error) and the part you have chosen is better than the part they have suggested.

Both parts appear to be stable at a gain of 2

Your CMRR (the ability of the amp to reject signals that are common to both inputs) is not important. The PSRR (the amps ability to reject noise on the power supply) is not important. Slew rate (how quickly the output can change) is not important (temperature does not change in microseconds).

I see no reason why you cannot drop in your suggested replacement.

Hope this helps
 
Mr. Nayor,
Thank you for such a complete answer. Not only does it allow me to move forward with using the sub chip but is most educational as to the "why and how" of the usage.

I am most appreciative,

woodturner550 :)
 
Status
Not open for further replies.

Latest threads

New Articles From Microcontroller Tips

Back
Top