problem in MikroC coad for LCD

[Qaisar Azeemi]

so what i have to do....

 

[DJ.]

is it compiler error?

 

[DJ.]

i have tried these and it is working...

int adc_rd,k=1;
char data_x[5][5];

void main() {

do
{
adc_rd=ADC_Read(1);
IRP_bit = 1; //always enable this before absolute vars
datax[k][0]=adc_rd/10;
datax[k][1]=adc_rd%10;
irp_bit = 0; // disable it just after using the absolute vars
k++;
if(k==10)k=0;
delay_ms(1000);
}while(1);
}

 

[Mr RB]

MikroC compiler is not capable to set IRP bit.
...

Where did you get that info?

The MikroC compiler will handle bank bits automatically.

 

[DJ.]

Hi RB,

I got these information from the one of the MikroC members... MikroC compiler forum....
And here above post does mean that it is not capable to IRP bit manually...

And it will do the automatic bank switching for the PIC18..

 

[Mr RB]

Thanks for the info, I checked the help file in MikroC and found this;
"Limits of Indirect Approach Through FSR
Pointers with PIC16 are “near”: they carry only the lower 8 bits of the address. Compiler will automatically clear the 9th bit upon startup, so that pointers will refer to banks 0 and 1. To access the objects in banks 3 or 4 via pointer, user should manually set the IRP, and restore it to zero after the operation. The stated rules apply to any indirect approach: arrays, structures and unions assignments, etc.

Note: It is very important to take care of the IRP properly, if you plan to follow this approach. If you find this method to be inappropriate with too many variables, you might consider upgrading to PIC18.

Note: If you have many variables in the code, try rearranging them with the linker directive absolute. Variables that are approached only directly should be moved to banks 3 and 4 for increased efficiency."

I have never experienced the issue myself as arrays etc are loaded by the compiler into the first ram banks, so it has never been an issue for me on PIC16F devices.

I still don't understand what the problem is with the OPs code, unless he has manually forced arrays into the last banks or has so much RAM used the compiler has had no choice but to put an array in the last banks?

 

[Qaisar Azeemi]

Thanks God, my problem is solved i used RAM Saver technique.