Just by looking at it very fast, I think you'll have to place the resistor (of, say, 10K) in the collector (between 9V and the second transistor's collector), and remove the resistor from the emitter (connecting the emitter to ground).
I don't really get the purpose of the top LDR (between +9V and collector of the first BJT). Maybe you could explain a bit better what u'r trying to do?
Another thing, why going with a common collector, when it's muc easier (and appropriate) to go with common emitter configuration?
TI|CP